x^2+2.3x-5.5=0

Solution for x^2+2.3x-5.5=0 equation:

x^2+2.3x-5.5=0

a = 1; b = 2.3; c = -5.5;
Δ = b2-4ac
Δ = 2.32-4·1·(-5.5)
Δ = 27.29
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.3)-\sqrt{27.29}}{2*1}=\frac{-2.3-\sqrt{27.29}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.3)+\sqrt{27.29}}{2*1}=\frac{-2.3+\sqrt{27.29}}{2}
$